
Variable Content
TTL:Chap
D–2
Publication
17466.8 - April 1997
Negative
Decimal V
alues
In two’s complement notation, the far left position is always 1 for
negative values. The equivalent decimal value of the binary number
is obtained by subtracting the value of the far left position, 32768,
from the sum of the values of the other positions. In the figure
below (all positions are 1), the value is 32767 – 32768 = –1. For
example:
1111
1000 0010 001
1 =
(2
14
+2
13
+2
12
+2
11
+2
5
+2
1
+2
0
) - 2
15
=
(16384+8192+4096+2048+32+2+1) - 32768 =
30755 - 32768 = -2013.
10 1 111 1111 111 111
1x2
14
=
16384
1x2
15
=
1
This position is always 1 for negative numbers
1x2
13
=
8192
1x2
12
=
4096
1x2
11
=
2048
1x2
10
=
1024
1x2
9
=
512
1x2
8
=
256
1x2
7
=
128
1x2
6
=
64
1x2
5
=
32
1x2
4
=
16
1x2
3
=
8
1x2
2
=
4
1x2
1
=
2
1x2
0
=
1
16384
8192
4096
2048
1024
512
256
128
64
32
16
8
4
2
1
32767
Commentaires sur ces manuels